InterviewSolution
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Two heavy particles having masses `m_(1)` and `m_(2)` are situated in a plane perendicular to line `AB` at a distance or `r_(1)` and `r_(2)` respectively. a. What is the moment of inertia of the system about axis `AB`? b. What is the moment of inertia of the system about an axis passing through `m_(1)` and perpendicular to the line joining `m_(1)` and `m_(2)`? c. What is the moment of inertia of the system about an axis passing through `m_(1)` and `m_(2)`? |
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Answer» a. Moment of inertia of the particle on the left `I_(1)=m_(v)r_(1)^(2)`,. Moment of inertia of the particle on the right is `I_(2)=m_(2)r_(1)^(2)`. Moment of inertia of the system `AB` is `I=I_(1)+I_(2)=m_(1)r_(2)^(2)+m_(2)r_(2)^(3)` b. Moment of inertia of the particle on the left is `I_(1)=0`. Moment of inertia of the particle on the right is `I_(2)=m_(2)(r_(1)+r_(2))^(2)`. moment of inertia of the system about the given axis is `I=I_(1)+I_(2)=0+m_(2)(r_(1)+r_(2))^(2)` c. Moment of inertia of the particle on theleft is `I_(1)=0` Moment of inertia of the particle on the right is `I_(2)=0` Moment of inertia of the system about the given axis is `I=I_(1)+I_(2)=0+0` |
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