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TWO identical conducting spheres carrying different chargesattract each other with a force F when placed in air mediumat a distance d' apart. The spheres are brought into contactand then taken to their original positions. Now the twospheres repel each other with a force whose magnitude isequal to that of the initial attractive force. The ratio betweeninitial charges on the spheres is[Kerala PET 2008] |
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Answer» 1is to 1ratio between initial charges on the sphere Since the two charges (spheres) attract, they will be opposite in sign, ie, q1 and –q2.Force, F= k * q1 * q2/ d2After touching, charge on each will be (q1 - q2)/2.New force, F=k*[(q1 - q2)/2]2/ d2.Since both the force are same(given in question)So, on solving by quadratic equations, we getq1/ q2 = -(3 + √(8)) or (-3 + √(8)) |
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