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Two identical piano wires have fundemental frequency of `600 vib//sec`, when kept under the same tension. What frectional increase in the tension of one wire will lead to the occurrence of six beats per second when both wires vibrate simuitaneously. |
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Answer» Correct Answer - `2%` `f = (1)/(lambda) sqrt((T)/(mu))` `lnf = -lnlambda + (1)/(2)lnT - (1)/(2)ln mu` `(1)/(f) (df)/(dT) = 0 + (1)/(2) (1)/(T) - 0` `(df)/(f) = (1)/(2)(dT)/(T)` `(dT)/(T) = (2df)/(f) = (2 xx 6)/(600) = (2)/(100)` `%` change `= (2)/(100) xx 100 = 2%` |
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