Two infinite parallel,non- conducting sheets carry equal positive charge density `sigma` ,One is placed in the `yz` plane other at distance `x=a` Take potential `V=0` at `x=0` thenA. for `0 le x le a`, potential `V = 0`B. for `x ge a`, potential `V = (sigma)/(epsilon_0)(x - a)`C. for `x ge a`, potential `V = (sigma)/(epsilon_0)(x - a)`D. for `x le 0`, potential `V = (sigma)/(epsilon_0) x`

Two infinite parallel,non- conducting sheets carry equal positive char

1.	Two infinite parallel,non- conducting sheets carry equal positive charge density `sigma` ,One is placed in the `yz` plane other at distance `x=a` Take potential `V=0` at `x=0` thenA. for `0 le x le a`, potential `V = 0`B. for `x ge a`, potential `V = (sigma)/(epsilon_0)(x - a)`C. for `x ge a`, potential `V = (sigma)/(epsilon_0)(x - a)`D. for `x le 0`, potential `V = (sigma)/(epsilon_0) x`
Answer» Correct Answer - a.,c.,d. `0 le x le a, V_x = [- underset(0)overset(x)(int) E_x d x]+ V_((0)) = 0` `("as" E_x = 0)` `x ge a, V = - underset(a)overset(x)(int) E_x d x + V_((a))` =`[- underset(a)overset(x)(int) (sigma)/(epsilon_0) dx] + V_((a)) = -(sigma)/(epsilon_0)(x - a) = (- sigma)/(epsilon_0) (x - a)` `x le 0, V = - underset(a)overset(x)(int) E_x d x + V_((0)) [ because E_x = (-sigma)/(epsilon_0)]` =`- (-(sigma)/(epsilon_0) x) + V_((0)) = (sigma)/(epsilon_0) x`.

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