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Two lamps, one ratein parallel to electric mains supply. Find thethe line, if the supply voltage is 220 v.d 100 W: 220 V, and the other 60 W; 220 V. are connectedcurrent drawn by two bulbs from

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Power = P = 100 WVoltage = V = 220vResistance = R

P = V²/R100 = 220×220/RR = 220× 220/100 = 484Ω==========================Power = P = 60 WVoltage = V = 220vResistance = R

P = V²/R60 = 220× 220/RR = 220× 220/60 = 806.7Ω=========================As the resistors are connected in parallel ,total resistance = 1/R

1/R = 1/484 + 1/806.7 = 806.7 + 484/484×806.7 = 1290.7/390442.8R =390442.8/1290.7 = 302.5 ohms Total resistance= 302.5Ω

I = current

V = IR220 = I× 302.5

I = 220/302.5 = 0.73 A

The current drawn is 0.73 A



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