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Two liquid drop have diameters of 1 cm and 1.5 cm. The ratio of excess pressures inside them isA. `1:1`B. `5:3`C. `2:3`D. `3:2` |
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Answer» Correct Answer - D Excess pressure inside a liquid drop, `Delta p = (2S)/(R)` where, S is surface tension and R is radius of liquid drop. `:. (Delta p_(1))/(Delta p_(2)) = (R_(2))/(R_(1)) = (0.75)/(0.50) = (3)/(2)` |
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