Two masses m1 and m2 are attached to the end of a string which passes

1.	Two masses m1 and m2 are attached to the end of a string which passes over a pulley attached to the top of an inclined plane .the angle of inclination of the plane theta .if m1=10kg , m2=5kg, theta =30 .then what is the tension in the string?a.100N b.50N c.25N d.zero
Answer» In the FIGURE, from the FBD of the 10 kg mass, when we CONSIDER the forces PARALLEL to the surface of the plane, we get, $\sf{\longrightarrow T-50=10a\quad\quad\dots(1)}$ Here 10a is the net force acting on the 10 kg mass, where a is the net ACCELERATION of the system. From the FBD of the 5 kg mass, when we consider the vertical forces, we get, $\sf{\longrightarrow 50-T=5a\quad\quad\dots(2)}$ Here 5a is the net force. Adding (1) and (2), $\sf{\longrightarrow T-50+50-T=10a+5a}$ $\sf{\longrightarrow15a=0}$ $\sf{\longrightarrow a=0}$ Then (1) becomes, $\sf{\longrightarrow T-50=0}$ $\sf{\longrightarrow\underline{\underline{T=50\ N}}}$ Hence (b) is the answer.