Two metallic cylinder made of same material and radi r and 2r are join

1.	Two metallic cylinder made of same material and radi r and 2r are joined as shown in figure. If top endifixed and lower end of cylinder B is twisted by angle 6, then angle of twist for cylinder A is (both cyinder hasame length)14.
Answer» Let the total angle twisted by A and B is(not mentioned in question) and twist angle made by A and B will beθ1andθ2respectively.henceθ=θ1+θ2.......1>(totalangletwistediscontributionofindividualangulartwist)now the force applied produce the torque on B and a restoring torque is produce in A to counter torque of B this continuous till both the rods does not archives the condition of equilibrium.using the formula of torque in both cylinder A and B Torque clockwose by B = torque anticlockwise by A n* pi* (2r)4 theta2/ 2L = n * pi* (r)4 theta1/ 2L Theta1 = 16 * theta2 Hence Theta2 + 16 theta2 = theta Theta2 = theta/17 And Theta1 = 16 theta/17

Two metallic cylinder made of same material and radi r and 2r are joined as shown in figure. If top endifixed and lower end of cylinder B is twisted by angle 6, then angle of twist for cylinder A is (both cyinder hasame length)14.

Answer»

Let the total angle twisted by A and B is(not mentioned in question) and twist angle made by A and B will beθ1andθ2respectively.henceθ=θ1+θ2.......1>(totalangletwistediscontributionofindividualangulartwist)now the force applied produce the torque on B and a restoring torque is produce in A to counter torque of B this continuous till both the rods does not archives the condition of equilibrium.using the formula of torque in both cylinder A and B

Torque clockwose by B = torque anticlockwise by A

n* pi* (2r)4 theta2/ 2L = n * pi* (r)4 theta1/ 2L

Theta1 = 16 * theta2

Hence

Theta2 + 16 theta2 = theta

Theta2 = theta/17

And

Theta1 = 16 theta/17

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