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Two motor mechanics, Raju and Siraj, working together can overhaul a scooter in 6 hours. Raju alone can do the job in 15 hours. In how many hours can Siraj alone do it? |
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Answer» we know that, Number of hours Raju required to overhaul the scooter = 15 hours Let us consider number of hours Sriraj to overhaul the scooter = X hours Number of hours required by Raju and Sriraj together to do piece of work = 6 hours ∴ We can calculate, work done by Raju in 1 hour = 1/15 Work done by Sriraj in 1 hour = 1/x Work done by both Raju and Sriraj in a hour = 1/6 Work done by both Raju and Sriraj in 1 hour= 1/15 + 1/x = x+15/15x x+15/15x = 1/6 6x + 90 = 15x 9x = 90 x = 90/9 x = 10 ∴ Sriraj can do the work in 10 hours. |
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