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Two numbers are selected are random (withoutreplacement) from positive integers 2, 3, 4, 5, 6 and 7. Let X denote the largerof the two numbers obtained. Find the mean and variance of the probability distribution of X. |
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Answer» Here are some positive integers `(2,3,4,5,6,7)` from which two numbers are selected at random (without replacement) and from those selected numbers larger one is selected. Smallest pair that can be formed `(2,3)` and Largest pair `(6,7)` therefore minimum value for X is `3` and maximum is `7`. `P(X=3) = P{(2,3),(3,2)} = P(2,3) + P(3,2)``=1/6*1/5+1/6*1/5` `P(X=3) = 1/15`Similarly, `P(X=4) = 2/15` `P(X=5) = 1/5` `P(X=6) = 4/15` `P(X=7) = 1/3` `Mean = Sigmax . P(X=x)= 3*(1)/15+4*(2)/15+5*(3)/15+6*(4)/15+7*(5)/15` `=1/15[3+8+15+24+35]` `=85/15=5.67` `E(x^2)=3^2*1/15+4^2*2/15+5^2*3/15+144/15+245/15` `=1/15[9+32+75+144+245]``=33.67`Therefore, Variance `(x)= E(E^2)-E(X)^2` `=33.67-(5.67)^2``=1.52` |
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