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Find the probability distribution of the number of green balls drawnwhen 3 balls are drawn , one by one, without replacement from a bagcontaining 3 green and 5 white balls. |
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Answer» let no of green balls to be drawn be = Xpossibilities of X:`0, 1 , 2,3` `P(X=0)= (5/8)*(4/7)*(3/6)` `P(X=1) = (3*4*5)/(8*7*6)` `P(X=2)= 3*(2*3*5)/(8*7*6)` `P(X=3)= (3/8)*(2/7)*(1/6)` |
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