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An urn contains 4 white and 6 red balls. Four balls are drawn at randomfrom the urn. Find the probability distribution of the number of white balls. |
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Answer» Let X be the event of drawing white balls possibilities of X =0,1,2,3,4 ` P(X=0) = (.^6C_4)/.^(10C_4)` `P(X=1) = ((.^9C_1)*(.^6C_3))/(.^10C_4)` `P(X=2) = ((.^4C_2)*(.^6C_2))/(.^10C_2)` `P(X=3) = ((.^4C_3)*(.^6C_3))/(.^10C_4)` `P(X=4) = (.^4C_4)/(.^10C_4)` |
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