1.

An urn contains 4 white and 6 red balls. Four balls are drawn at randomfrom the urn. Find the probability distribution of the number of white balls.

Answer» Let X be the event of drawing white balls
possibilities of X =0,1,2,3,4
` P(X=0) = (.^6C_4)/.^(10C_4)`
`P(X=1) = ((.^9C_1)*(.^6C_3))/(.^10C_4)`
`P(X=2) = ((.^4C_2)*(.^6C_2))/(.^10C_2)`
`P(X=3) = ((.^4C_3)*(.^6C_3))/(.^10C_4)`
`P(X=4) = (.^4C_4)/(.^10C_4)`


Discussion

No Comment Found