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Two plates are `2cm` apart, a potential difference of `10` volt is applied between them, the electric field between the plates isA. `20 N//C`B. `500 N//C`C. `5 N//C`D. `250 N//C` |
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Answer» Correct Answer - B `E = (V)/(d) = (10)/(2 xx 10^(-2)) = 500 N//C` |
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