InterviewSolution
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InterviewSolution
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Two reaction : `X rarr` Products and `Y rarr` Products have rate constants `k_(1)` and `k_(2)` at temperature `T` and activation energies `E_(1)` and `E_(2)`, respectively. If `k_(1) gt k_(2)` and `E_(1) lt E_(2)` (assuming that the Arrhenius factor is same for both the Products), then (I) On increaisng the temperature, increase in `k_(2)` will be greater than increaisng in `k_(1)`. (II) On increaisng the temperature, increase in `k_(1)` will be greater than increase in `k_(2)`. (III) At higher temperature, `k_(1)` will be closer to `k_(2)`. (IV) At lower temperature, `k_(1) lt k_(2)`A. At higher temperature `K_(A)` will be greater than `K_(B)`B. At lower temperature `K_(A)` and `K_(B)` will differ more and `K_(A) gt K_(B)`C. As temperature rises `K_(A)` and `K_(B)` will be close to each other in magnitudeD. All of these |
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Answer» Correct Answer - d `K_(A)=Ae^(-E_(A)//RT)` and `K_(B)=Ae^(-E_(B)//RT)` Also `K_(A) gt K_(B)` `E_(A) lt E_(B)` Now notice that all the given facts are satisfied. |
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