InterviewSolution
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InterviewSolution
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Two reactions `A rarr` products and `B rarr` products have rate constants `k_(a)` and `k_(b)` respectively at temperature `T` and activation energies are `E_(a)` and `E_(b)` respectively. If `k_(a) gt k_(b)` and `E_(a) lt E_(b)` and assuming the freuency factor `A` in both the reactions are same thenA. on increasing temperature `k_` will be greater than `k_(b)`B. At lower temperature `k_(a)` and `k_` will differ moreC. As temperature rises `k_(a)` and `k_(b)` will be close to each other in magnitudeD. All of the above are correct |
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Answer» Correct Answer - D ln `k_(a) = A - E_(a)//RT`, ln `k_(b) = A - E_(b)//RT` As temperature rises `E//RT` become negligible. |
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