InterviewSolution
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InterviewSolution
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Two reactions having their energy of activation `E_(1)` and `E_(2)` temperature coefficients `T_(c_(1))` and `T_(c_(2))` respectively within the temperature 300 and `310K`. The ratio of their temperature coefficient is:A. `e^(E_(1)//E_(2))`B. `e^((E_(1)-E_(2))xx10^(-4)//R)`C. `10^(E_(1)//E_(2))`D. `e^((E_(1) - E_(2))//4)` |
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Answer» Correct Answer - `(b)` `2.303 log t_(C_(1)) = (E_(1))/(R) [(T_(2) - T_(1))/(T_(1) T_(2))]` `2.303 log T_(c_(2)) = (E_(2))/(R) [(T_(2) - T_(1))/(T_(1) T_(2))]` `2.303 [log T_(C_(1)) - log T_(C_(2))]` `= ((E_(1) - E_(2)))/(R) xx [(310 - 300)/(300xx310)]` `:. 2.303 log ((T_(C_(1)))/(T_(C_(2)))) = [(E_(1) - E_(2))/(R)] xx 1.07xx10^(-4)` or In `(T_(c_(1)))/(T_(C_(2))) = [(E_(1) - E_(2))/R] xx 10^(-4)` `:. (T_(c_(1)))/(T_(c_(2))) = e^([(E_(1) - E_(2))/(R)]xx10^(-4))` |
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