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Two reactiosn of same order have equal pre-exponential factors but their activation energies differ by 41.9 J/mol. Calculte the ratios between rate constant of these reactions at 600 K |
Answer» Correct Answer - `0.002` Use the relation `log_(10)k=log_(10)A-(E)/(2.303RT)" ".....(i)` `log_(10)k_(1)=log_(A)-(E_(1))/(2.303xx8.314xx600) " ".....(ii)` `log_(10)k_(2)=log_(A)-(E_(2))/(2.303xx8.314xx600) " ".....(iii)` `E_(1)-E_(2)=41.95//"mol"" ".....(iv)` Substract eq. (ii) from eq. (ii) to determine the ratio |
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