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Two resistors when connected in parallel haveequivalent resistance of 5/3 ohnmthe equivalent resistance is 12 ohm. Find theirresistances.. When in series[Ans. 2 Ω,10 Ω]

Answer»

when in parallel R=R1R2/R1+R2=5/3and in series R1+R2=125/3=R1R2/12R1R2=5/3*12=5*4=20R1=20/R2hence20/R2+R2=1220+R2^2=12R2R2^2-12R2+20=0R2=-b+-√b^2-4ac/2aR2=12+-√144-80/2R2=12+-8/2R2=4/2 or 20/2=2ohm and 10ohm



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