1.

two resistors with resistance 5 ohm and 10 ohm are connected to a battery PD 6 volt so as to obtain minimum and Maximum current how will you connect resistance in each case calculate the strength of total current in the circuit in two case​

Answer»

Answer:

For minimum resistance , : Parellel

1/5 + 1/ 10 = 1/R

3/10 = 1/R

10 / 3 = R

3.333 = R

Now , for maximum resistance : Series

5 + 10 = R

15 = R

Now TOTAL CURRENT when connected to series,

V = I / R

6 = I / 3.33

6* 10/3 = I

20 Ampere = I

Now, total current when connected in parallel ,

V = I/R

6= I / 15

6*15 = I

90 Ampere = I

Explanation:

Hope It will help u


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