Two resistors X and Y of resistances 2 omega and 3 omega respectively are first joined in parallel and then in series. In each case the voltage supplied is 5 V. (i) Draw circuit diagrams to show the combination of resistors in each case. (ii) Calculate the voltage across the 3 Q resistor in the series combination of resistors.

Two resistors X and Y of resistances 2 omega and 3 omega respectively

1.	Two resistors X and Y of resistances 2 omega and 3 omega respectively are first joined in parallel and then in series. In each case the voltage supplied is 5 V. (i) Draw circuit diagrams to show the combination of resistors in each case. (ii) Calculate the voltage across the 3 Q resistor in the series combination of resistors.
Answer» Solution :(i) APPROPRIATE circuit diagrams are drawn below (zz) Total resistance of circuit in SERIES arrangement R = X + Y = 2 + 3 = 5 `omega` `therefore`Circuit CURRENT`I=(V )/(R )=(5V)/(5 omega)=1 A` `therefore` Voltage across the 3`omega` resistor, `V_(y) = I xx Y = 1 A xx3 omega = 3V`.