InterviewSolution
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Two sound waves of relative intensities400:1 show interference. The ratio ofintensity at the maxima to minima is closeto:(A) 21/19(B) 11/9(C) 401/399441361 |
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Answer» The ratio is given by. (√i1+√i2)²/((√i1-√i2)²= (√400+1)²/(√400-1)²= (20+1/20-1)² = (21/19)² = 441/361 option D should be correct. and root should not be there in the option |
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