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Two stones, having masses in the ratio of 3 : 2, aredropped from the heights in the ratio of 4: 9. Theratio of magnitudes of their linear momenta justbefore reaching the ground is (neglect air resistance) |
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Answer» v²=u²+2as here in both case u will be zero momentum(p)=velocity × mass here we need v v=√2as (a=g=10m/s²) in first case v = √2×10×4 =4√5 p = 4√5 × 3 = 12√5in case 2 v=√2×10×9 = 6√5 p= 6√5 × 2 =12√5HENCE RATIO IS 1:1 thanku |
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