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InterviewSolution
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Two substances `A (t_(1//2) = 5 min)` and `B(t_(1//2) = 15 min)` follow first order kinetics and are taken in such a way that initially `[A] = 4[B]`. The time after which the concentration of both the substance will be equal is `5x min`. Find the value of `x`. |
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Answer» Correct Answer - 3 `|{:([A],[B],"Time (min)",),(4a,a,0,),(2a,-,5 min,),(a,-,10 min,),(a//2,a//2,15 min,):}|` `:. 5x = 15 min` `x = 3 min`Correct Answer - 3 `|{:([A],[B],"Time (min)",),(4a,a,0,),(2a,-,5 min,),(a,-,10 min,),(a//2,a//2,15 min,):}|` `:. 5x = 15 min` `x = 3 min` |
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