Two tall buildings are 200 m apart. With what speed must a ball be thr

1.	Two tall buildings are 200 m apart. With what speed must a ball be thrown horizontally from a window 540 m above the groundinone building so as to enter a 50 m high window in the other building?
Answer» This question is based on concept of horizontal projectile .use trajectory equation of Horizontal projectile. e.g Y = gx²/2u² where Y is the displacement of object in y-component wrt to frame , x is the displacement of object in x -component wrt frame . g is acceleration due to gravity and u is intial velocity. here ,Y = 200 m x = 540 -50 = 490 m now, 200 = 10 (490)²/2u² 40 = (490)²/u² u² = (490)²/40 u = 490/2√10=77.47 m/s

Two tall buildings are 200 m apart. With what speed must a ball be thrown horizontally from a window 540 m above the groundinone building so as to enter a 50 m high window in the other building?

Answer»

This question is based on concept of horizontal projectile .use trajectory equation of Horizontal projectile.

e.g Y = gx²/2u²

where Y is the displacement of object in y-component wrt to frame , x is the displacement of object in x -component wrt frame . g is acceleration due to gravity and u is intial velocity.

here ,Y = 200 m x = 540 -50 = 490 m

now,

200 = 10 (490)²/2u²

40 = (490)²/u²

u² = (490)²/40

u = 490/2√10=77.47 m/s

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Two tall buildings are 200 m apart. With what speed must a ball be thrown horizontally from a window 540 m above the groundinone building so as to enter a 50 m high window in the other building?

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