Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of `72 km h^(-1)` in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates by `1 ms^(-2)`. If after 50s, the guard of B just brushed past the driver of A, what was the original distance between them ?

Two trains A and B of length 400 m each are moving on two parallel tra

1.	Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of `72 km h^(-1)` in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates by `1 ms^(-2)`. If after 50s, the guard of B just brushed past the driver of A, what was the original distance between them ?
Answer» For train A: Initial velocity, u = 72 km/h = 20 m/s Time, t = 50 s Acceleration, `a_I = 0` (Since it is moving with a uniform velocity) From second equation of motion, distance `(s_\|)`covered by train A can be obtained as: `s_\|=ut+1/2a_\|t^2`= 20 × 50 + 0 = 1000 m For train B: Initial velocity, u = 72 km/h = 20 m/s Acceleration, `a = 1 m//s^2` Time, t = 50 s From second equation of motion, distance `(s_(\|\|))`covered by train A can be obtained as: `S_(\|\|)=ut+1/2at^2` `=20xx50+1/2xx1xx(50)^2=2250 m` Hence, the original distance between the driver of train A and the guard of train B is 2250 – 1000 = 1250 m

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