InterviewSolution
Saved Bookmarks
| 1. |
Two trains ` A and B` of length `400 m` each are moving on two parallel tracks with a uniform speed of ` 72 km h^(-1)` in the same direction with ` A` ahead of `B` .The driver of B decides to overtake Aand accelerates by 1m/s².if after 50s ,the guard of B just passes the driver of A , what was the original distance between them ?A. 750 mB. 1000 mC. 1250 mD. 2250 m |
|
Answer» Correct Answer - C For train A, `u_A = 72 km h^(-1) = 72 xx 5/18 m s^(-1) = 20 m s^(-1) , a_A = 0`, t = 50 s, `therefore S_A = u_(A)t - (20)(50) = 1000 m` For train B, `U_b = 72 km h^(-1) = 72 xx 5/18 m s^(-1) = 20 m s^(-1)` `a_B = 1 m s^(-2)` , t = 50 s `therefore S_B = u_(B)t + 1/2 a_(B)t^(2)` `= (20 xx 50) + 1/2 xx 1 xx (50)^(2) = 2250` m Original distance between A and `B = S_B - S_A = 2250 m - 1000 m = 1250 m` |
|