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Two Trains Each 100 M Long, Moving In Opposite Directions, Cross Each Other In 8 Seconds. If One Is Moving Twice As Fast The Other, Then The Speed Of The Faster Train Is ? |
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Answer» SPEED of the faster train = 2x m/sec. RELATIVE speed of train = (x + 2x) m/sec = 3x m/sec. Total DISTANCE = (100 + 100)m = 200m 3x = 200/8 => 24x = 200 => x = 25/3 So speed of the faster train = 2 * 25/3 m/sec = 50/3 m/sec = 50/3 * 18/5 = 60 km/hr. speed of the faster train = 2x m/sec. Relative speed of train = (x + 2x) m/sec = 3x m/sec. Total distance = (100 + 100)m = 200m 3x = 200/8 => 24x = 200 => x = 25/3 So speed of the faster train = 2 * 25/3 m/sec = 50/3 m/sec = 50/3 * 18/5 = 60 km/hr. |
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