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Two tuning forks A and B gives 6 beat/s. The fork A resonates with a closed end air column of length 15cm and the fork B with an open air column of length 30.5cm . If the air in both the cases vibrates in the air fundamental modes, then the frequencies of fork A and B will beA. 354 and 360HzB. 366 and 360HzC. 360 and 354 HzD. 360 and |
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Answer» Correct Answer - B Let `n_A "and " n_B` denotes the frequency of tuning fork A and B . Then `n_A = (v)/(4(15)) = v/60 " and " n_B = (v)/(2(30.5)) = v/61` As `n_A gt n_B " " therefore n_A -n_B = 6` `v/60 - v/61 = 6 therefore v[(61-60)/(60xx61)]=6` `n_A = v/60 = (6xx60xx61)/(60) = 366` `n_B=v/61=(6xx60xx61)/(61) = 360Hz` |
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