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Two underground cables having conductor resistances of 0.7 Ω and 0.5 and insulation resistance of 300 M Ω respectively are joind (i) in series (ii) in parallel. Find the resultant conductor and insulation resistance. |
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Answer» (i) The conductor resistance will add like resistances in series. However, the leakage resistances will decrease and would be given by the reciprocal relation. Total conductor resistance = 0.7 + 0.5 = 1.2 Ω If R is the combined leakage resistance, then 1/R = 1/300 + 1/600 ∴ R = 200MΩ (ii) In this case, conductor resistance is = 0.7 × 0.5/(0.7 + 0.5) = 0.3. Ω (approx) Insulation resistance = 300 + 600 = 900 M Ω |
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