1.

Two underground cables having conductor resistances of 0.7 Ω and 0.5 and insulation resistance of 300 M Ω respectively are joind (i) in series (ii) in parallel. Find the resultant conductor and insulation resistance.

Answer»

(i) The conductor resistance will add like resistances in series. However, the leakage resistances will decrease and would be given by the reciprocal relation. 

Total conductor resistance = 0.7 + 0.5 = 1.2 Ω 

If R is the combined leakage resistance, then

1/R = 1/300 + 1/600

∴ R = 200MΩ

(ii) In this case, conductor resistance is 

= 0.7 × 0.5/(0.7 + 0.5) = 0.3. Ω (approx) 

Insulation resistance = 300 + 600 = 900 M Ω



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