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Two Urns Contain Respectively 2 Red 3 White And 3 Red,5 White Balls.one Ball Is Drawn At Random From The First Urn And Transferred Into The Second.a Ball Is Now Drawn From The Second Urn And It Turns Out To Be Red. What Is The Probability That The Transferred Ball Was White? |
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Answer» <P>According to baye's theorem: p(no of way to DRAWN a BALL from 2nd urns is red and ball transferred from 1 urns)=(3c1/5c1)*(3c1/9c1)=9/45 Total=(2c1/5c1)*(4c1/9c1)+(3c1/5c1)*(3c1/9c1)=17/45 so probability=(9/45)/(17/45)=9/17. According to baye's theorem: p(no of way to drawn a ball from 2nd urns is red and ball transferred from 1 urns)=(3c1/5c1)*(3c1/9c1)=9/45 Total=(2c1/5c1)*(4c1/9c1)+(3c1/5c1)*(3c1/9c1)=17/45 so probability=(9/45)/(17/45)=9/17. |
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