1.

Two Vessels A And B Contain Spirit And Water Mixed In The Ratio 5:2 And 7:6 Respectively. Find The Ratio In Which These Mixture Be Mixed To Obtain A New Mixture In Vessel C Containing Spirit And Water In The Ratio 8:5 ?

Answer»

Let's assume C.P. of SPIRIT = Re. 1 per LITRE.

Spirit in 1 litre mix. of A = 5/7 litre. So C.P of 1 litre mix in A = Re. 5/7.

Spirit in 1 litre mix. of B = 7/13 litre. So C.P of 1 litre mix in B = Re. 7/13.

Spirit in 1-litre mix. of C = 8/13 litre. So C.P. of 1 litre mix in C = Re. 8/13.

By RULE of an ALLEGATION, we have required ratio X:Y.

(5/7) (7/13)

(8/13)

(1/13) (9/91)

So, required ratio = 1/13 : 9/91 = 7:9.

Let's assume C.P. of spirit = Re. 1 per litre.

Spirit in 1 litre mix. of A = 5/7 litre. So C.P of 1 litre mix in A = Re. 5/7.

Spirit in 1 litre mix. of B = 7/13 litre. So C.P of 1 litre mix in B = Re. 7/13.

Spirit in 1-litre mix. of C = 8/13 litre. So C.P. of 1 litre mix in C = Re. 8/13.

By rule of an allegation, we have required ratio X:Y.

(5/7) (7/13)

(8/13)

(1/13) (9/91)

So, required ratio = 1/13 : 9/91 = 7:9.



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