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Two Vessels A And B Contain Spirit And Water Mixed In The Ratio 5:2 And 7:6 Respectively. Find The Ratio In Which These Mixture Be Mixed To Obtain A New Mixture In Vessel C Containing Spirit And Water In The Ratio 8:5 ? |
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Answer» Let's assume C.P. of SPIRIT = Re. 1 per LITRE. Spirit in 1 litre mix. of A = 5/7 litre. So C.P of 1 litre mix in A = Re. 5/7. Spirit in 1 litre mix. of B = 7/13 litre. So C.P of 1 litre mix in B = Re. 7/13. Spirit in 1-litre mix. of C = 8/13 litre. So C.P. of 1 litre mix in C = Re. 8/13. By RULE of an ALLEGATION, we have required ratio X:Y. (5/7) (7/13) (8/13) (1/13) (9/91) So, required ratio = 1/13 : 9/91 = 7:9. Let's assume C.P. of spirit = Re. 1 per litre. Spirit in 1 litre mix. of A = 5/7 litre. So C.P of 1 litre mix in A = Re. 5/7. Spirit in 1 litre mix. of B = 7/13 litre. So C.P of 1 litre mix in B = Re. 7/13. Spirit in 1-litre mix. of C = 8/13 litre. So C.P. of 1 litre mix in C = Re. 8/13. By rule of an allegation, we have required ratio X:Y. (5/7) (7/13) (8/13) (1/13) (9/91) So, required ratio = 1/13 : 9/91 = 7:9. |
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