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Two vibrating tuning forks produce progressive waves given by `y_(1)=sin500pit` and `y_(2)=2sin506pit`. Number of beats produced per minute is:A. `360`B. `180`C. `3`D. `60` |
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Answer» Correct Answer - B The reach the solution the given wave equation ust be compared with standard equation of progressive wave, so `y_1=4sin500pit` .(i) `y_2=2sin506pit` .(ii) Comparing Eqs. (i) and (ii) with `y=asinomegat` ..(iii) we have `omega_1=500pi` `impliesf_1=(500pi)/(2pi)=250beats//s` and `omega_2=506pi` `impliesf_2=(506pi)/(2pi)=253beats//s` Thus, number of beats produced `=f_2-f_1-253-250-3 beats//s` `=3xx60(beats)/(min)=180beats//min` |
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