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Two vibrating tuning forks produce progressive waves given by `y_(1)=sin500pit` and `y_(2)=2sin506pit`. Number of beats produced per minute is:A. `360`B. `180`C. `3`D. `60`

Answer» Correct Answer - B
The reach the solution the given wave equation ust be compared with standard equation of progressive wave,
so `y_1=4sin500pit` .(i)
`y_2=2sin506pit` .(ii)
Comparing Eqs. (i) and (ii) with
`y=asinomegat` ..(iii)
we have `omega_1=500pi`
`impliesf_1=(500pi)/(2pi)=250beats//s`
and `omega_2=506pi`
`impliesf_2=(506pi)/(2pi)=253beats//s`
Thus, number of beats produced
`=f_2-f_1-253-250-3 beats//s`
`=3xx60(beats)/(min)=180beats//min`


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