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Two water taps together can fill a tank in 15/8hours . the tap with longer diameter takes 2hours less then the tap with smaller diameter to fill the tank separately . find the in which each tap can fill the tank separately |
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Answer» here is your answer!Explanation:Let there be two taps A and B and let A be the tap with longer diameter than tap B then.tap A takes 2 hours less than tap B if tap B is taking X hours the. Tap A would take (X-2) hoursNow,1/x + 1/(x-2) = 8/15= x-2 + x / x^2-2x =8/15= (2x-2 )15 = 8(x²-2x)= 30X - 30 = 8x² - 16x=8x²-16x-30x+30= 0=8x² -46X +30 = 0divide the eq by 2 we get=4x²-23x+15=0=(4x²-20x)-(3x+15)=0=4x(x-5)-3(x-5)=0=(4x-3)(x-5)=0x=3/4 or x=5if x=5then x-2=3therefore TIME taken by tap A=xhours=5hours and time taken by tap B=x-2 hours =5-2=3 hours.hope it helpsplease MARK as brainliesthappy holiall the best! |
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