Two wires A and B of the same material and having same length, have th – InterviewSolution

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Two wires A and B of the same material and having same length, have their cross sectional areas in the ratio 1 : 6. What would be the ratio of heat produced in these wires when same voltage is applied across each?

Answer»

A_A : A_B = 1 : 6

H = V²t/R and \(R=\frac{pl}{A}\)

\(H_A=\frac{V^2t}{pl/A_A};\) \(H_B=\frac{V^2t}{pl/A_B}\)

\(=\frac{H_A}{H_B}=\frac{V^2\times A_A}{V^2tA_B}\)

\(\Rightarrow \frac{H_A}{H_B}=\frac{A_A}{A_B}=1:6\)

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