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Two wires of the same material and length but diameter in the ratio 1:2 are stretched by the sameforce. The ratio of potential energy per unit volume for the two wires when stretched will be10.(D) 16: 1

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Elastic energy per unit volume: E = 1/2 * Stress * Strain

Using Hooke's law: Strain = Stress/Y

E = (Stress)^2/2Y = F^2/2Y A^2 where A = πD^2/ 4E = 8F^2/π^2D^4Y

∴ E1/E2 = (D2/D1)^4 (∵ F and Y are same for both )GIven : D1/D2 = 1/2

E1/E2 = (2/1)^4 = 16/1

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