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Under a constant pressure head, the rate of streamlined volume flow of a liquid through a capillary tube is V. if the length of the capillary tube is double and diameter of the bore is halved, find the rate of flow of the liquid through the capillary tube. |
Answer» `V = (pi p r^(4))/(8eta l) or V prop (r^4)/(l)` `:. (V_1)/(V) = ((r//2)^(4))/(r^4) xx l/(2l) = 1/32 or V_(1) =V/32`. |
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