1.

Under a pressure head, the rate of orderly volume of liquid flowing through a capillary tube is Q. If the length of capaillary tube were doubled and diameter of the bore is halved, the rate of flow would becomeA. `(Q)/(4)`B. 16 QC. `(Q)/(8)`D. `(Q)/(32)`

Answer» Correct Answer - D
As, `Q = (pi p r^(4))/(8 eta l)` and `Q_(1) = (pi r(r//2)^(4))/(8 eta (2l)) = (Q)/(32)`


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