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Unit vectors along position vector and acceleration vector areandi +j | . What is the ratio ofmagnitudes of a, and a,(A) 3(B) 2(C) 1(D) 2 |
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Answer» Given the position vector is in +i direction. And the acceleration vector is (-1/√2i +1/√2j) so, the i component of acceleration vectors that is (-1/√2) is parallel to the position vector. so, it is aT and the j component is perpendicular to the position vector, so this is aR so, the ratio is of magnitude of aR/aT = |-1/√2/(1/√2)| = 1. option C . |
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