InterviewSolution
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InterviewSolution
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Use your brain power! M=(h_(2))/(h_(1))"…..(i)" M=(v)/(u)" …..(ii)" From equations (i) and (ii) what is the relation between h_(1), h_(2), u and v ? |
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Answer» Solution :From the given equations, we can SAY that, `(h_(2))/(h_(1))=(v)/(u)` According to Cartesian SIGN convention, for concave lens, `h_(2) and h_(1)` are always positive while v and u are always negative. `therefore" "(+h_(2))/(+h_(1))=(-v)/(-u)` SIMILARLY, for convex lens, when object is placed within the focal length, `h_(2) and h_(1)` are positive while v and u are negative. `therefore" "(+h_(2))/(+h_(1))=(-v)/(-u)` For all other positions of object, `h_(2) and u` are negative while, `h_(1) and v` are positive. `therefore" "(-h_(2))/(+h_(1))=(+v)/(-u)` |
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