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User off ~~`Find the approximate value of √0.037 using differential approxmations? |
Answer» Answer;Take y=x
Let x=0.04 and Δx=−0.003, Then, Δy=x+Δ −x
Δy=0.037 −0.04
=Δy+0.2 Now, dy is approximately equal to $$Δy$$ and is GIVEN by dy=(DXDY )∆x=2x1(−0.003)= 2 0.04 1 (−0.003)=−0.0075 Thus, the approximate value of 0.037
is 0.2−0.0075=0.1925 Hence, this is the answer. HOPE it helps you ✌️✅✅✅ |
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