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Usha swims in a 90 m longpool. She covers 180 m in one minuteby swimming from one end to the otherand back along the same straight path.Find the average speed and averagevelocity of Usha. |
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Answer» Length of the pool: 90mAverage speed:Speed= Distance/Timespeed=180/60speed=30 m/s Velocity:velocity=displacement/time displacement=0( Since she comes back to the same place) velocity=0 the average speed of usha is 3m s and her average velocity's s |
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