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Using Kirchoff’s rules determine the value of unknown resistance R in the circuit so that no current flows through 4Ω resistance. Also find the potential difference between A and D. |
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Answer» Applying Kirchhoff's loop rule for loop ABEFA, 9 + 6 + 4 × 0 + 2I = 0 I = 1.5 A ...(i) For loop BCDEB 3 + IR + 4 × 0 – 6 = 0 ∴ IR = 3 Putting the value of I from (i) we have \(\frac{3}{2}\times R=3\) \(\Rightarrow R=2\Omega\) Potential difference between A and D through path ABCD 9 - 3 - IR = VAD or 9 - 3 - \(\frac{3}{2}\times 2\) = VAD \(\Rightarrow\) VAD = 3V |
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