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Using listed informations, calculate `Delta_(r)G^(@)` (in kJ/mol) at `27^(@)C` `Co_(3)O_(4)(s)+4CO(g)rarr3Co(s)+4CO_(2)(g)` Given : At 300 K `DeltaH_(f)^(@)(kJ//mol)-891,-110.5,0.0,-393.5` `S^(@)(J//K-mol)102.5, 197.7, 30.0, 213.7`A. `-214.8`B. `-195.0`C. `-200.3`D. -256.45 |
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Answer» Correct Answer - D `Delta_(r)H^(@)=3.Delta_(f)H^(@)(CO,s)+4Delta_(f)H^(@)(CO_(2),g)` `-Delta_(f)H^(@)(Co_(3)O_(4),s)-4.Delta_(f)H^(@)(CO,g)` `Delta_(r)H^(@)=-"241 kJ/mol"` `Delta_(r)S^(@)=3xx30+4xx213.7-102.5-4xx197.7` = 51.5 J/K-mol `therefore" "Delta_(r)G^(@)=Delta_(r)H^(@)-T.Delta_(r)S^(@)` `=-241-(300xx51.5)/(1000)` `=-256.45"kJ/mol"` |
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