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V(m/s)4 m/sBased on Area Under the Curve :Find:Displacement between t = 7 sec to t = 10 sec.Acceleration at t = 2 sec, t = 9 sec, t = 12 sec.a between t = 5 sec to t = 10 sec.19.2 ms.571015t/sec) |
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Answer» 18= 20 ans. and 19 =25 and 20 =4-2/10-5 then it is your answer |
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