1.

Value of `gamma` for `CH_(4)` molecule is (Consider vibarational degree of freedom to be active).A. `4//3`B. `(13)/(12)`C. `(15)/(14)`D. `(17)/(15)`

Answer» Correct Answer - B
`C_(V) =3R+9R rArr12 R`
`C_(V) = 13 R`
`gamma=(C_(P))/(C_(V))=(13)/(12)`


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