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Value of `tan^(- 1){sin(cos^(- 1)sqrt(2/3))}` isA. `pi//4`B. `pi//2`C. `pi//3`D. `pi//6` |
Answer» `tan^(-1){sin(cos^(-1)sqrt(2/3))}` `=tan^(-1){sin(sin^(-1)sqrt(1/3))}=tan^(-1)(1)/sqrt(3)=(pi)/(6)` |
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