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Value of (tan1° tan2° tan3° ………..tan89°) is:1). 12). 893). Undefined4). 0 |
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Answer» We KNOW that, TAN(90 - θ) = cot(θ) tan 89 can be written as cot 1 [tan(90 - 1) = cot 1] So, tan 88 = cot 2 tan 87 = cot 3 up to tan 46 = cot 44 then middle one is tan 45 = 1 Hence the expression becomes tan 1 × tan 2...........tan 44 × tan 45 × cot 44..............cot 1 as tanθ × cotθ = 1 hence tan and cot GETS cancelled Thus the value that remain is tan 45 i.e. 1 |
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