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\vec{A}=3 \vec{i}+2 \vec{j}+2 \vec{k}, \vec{B}=\vec{i}-\vec{j}+2 \vec{k}, \text { find } \vec{A} \cdot \vec{B} |
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Answer» A.B= (3.1)+(2.(-1))+(2.2)= 3-2+4= 5 |
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