1.

\vec{A}=3 \vec{i}+2 \vec{j}+2 \vec{k}, \vec{B}=\vec{i}-\vec{j}+2 \vec{k}, \text { find } \vec{A} \cdot \vec{B}

Answer»

A.B= (3.1)+(2.(-1))+(2.2)= 3-2+4= 5



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