1.

velocity of sound in the atmosphere of a planet is 500ms^-(1). The minimum distance between the sources of sound and the obstacle to hear the echo, should be

Answer»

17 m
20 m
25 m
50 m

Solution :The minimum distance of source of sound and hear the ECHO,
`d=(vt)/(2)`
`t=0.1s,d=(500xx0.1)/(2)impliesd=25m`


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