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Viil) The wire of length and resistance ris stretched so that its radius of cross section is halved. What is its new resistance.a)5Rbyer04Rd) 16R |
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Answer» 4RExplanation:We KNOW that, R=¶L/A. (Just CONSIDER ¶ as RHO )Now,A'= πr'²A'=π(r/2)²A'=π(r²/4)A'=A/4Again, R'=¶L/A'R'=¶L/A/4R'=4¶L/ATherefore,R'=4R |
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